Hacks to Python

Some useful but mainly useless tricks to use in Python

Pipeline operator

Models

Miss your dear and dear pipeline operator in ...

Well, you can have it in Python too!

Implementation

Python

from functools import update_wrapper
from typing import Any, Callable, Optional


class Pipeline:
    def __init__(self, func: Optional[Callable] = None) -> None:
        if func is not None:
            update_wrapper(self, func)
            self.funcs: list[Callable] = [func]
        else:
            self.funcs: list[Callable] = []

    def __call__(self, *args: Any, **kwds: Any) -> Any:
        """
        self(*) => self.funcs[0](self.funcs[1](self.funcs[2](...)))
        """
        if len(self.funcs) == 0:
            return None
        res = self.funcs[-1](*args, **kwds)
        for func in reversed(self.funcs[:-1]):
            try:
                res = func(res)
            except Exception as e:
                print(f"Error encountered when executing {func} with parameter {res}:")
                raise e
        return res

    def __add__(self, func: Callable | "Pipeline") -> "Pipeline":
        """
        (f + g)(*) => f(g(*))
        """
        res = Pipeline()
        res.funcs += self.funcs
        if isinstance(func, Pipeline):
            res.funcs += func.funcs
        elif callable(func):
            res.funcs.append(func)
        else:
            raise TypeError(f"Unsupported type {type(func)}")
        return res

    def __radd__(self, func: Callable | "Pipeline") -> "Pipeline":
        res = Pipeline()
        if isinstance(func, Pipeline):
            res.funcs += func.funcs
        elif callable(func):
            res.funcs.append(func)
        else:
            raise TypeError(f"Unsupported type {type(func)}")
        res.funcs += self.funcs
        return res

    def __or__(self, func: Callable | "Pipeline"):
        """
        * | f | g => g(f(*))
        """
        return func + self

    def __ror__(self, func: Callable | "Pipeline" | Any):
        if isinstance(func, Callable) or isinstance(func, Pipeline):
            return self + func
        else:
            return self(func)


@Pipeline
def foo(a: int) -> list[int]:
    return list(range(a))


@Pipeline
def bar(b: list[int]) -> int:
    return max(b)


# Pipeline in Python???!!!
if __name__ == "__main__":
    func = bar + foo
    print(func(10))       # 9
    print(10 | foo | bar) # 9

How it works

The solution is simple:

Define a wrapper function that keeps the original functions inside (self.funcs is a list of callables)
Generate a new function upon operating at least one such function (e.g. pipeline operator | which is seen as or operation in Python, or adding two functions together like f+g <=> f(g(.)))
When calling such function, it will sequentially execute all the nested functions
Add some finishing touches, and you are good to go!

Multi-statement lambda expression

Models

Multi-statement lambda expressions are commonly supported in other languages, such as:

But wait! What about Python?

func = lambda a, b: a + b

Seems like Python only supports single-statement lambda expression... or is that so?

Well, you can have it too!

Implementation

Python

func = lambda a, b: (
    a := a + 1,
    b := b + 1,
    a + b,
)[-1]

Well, in python, the evaluation of a tuple is done sequentially, so you can use a tuple to mimic the behavior of a multi-statement lambda expression, where the return value could be specified by the index of element.

Note that in order to assign values in a tuple, you will need to use the walrus operator := introduced in Python 3.8. It will assign the value to the variable on the left, and return the value on the right, similar to the default behavior of = in C/C++ and many other languages.